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MHT CET · Maths · Functions

The domain of the function \(f(x)=\sqrt{x-1}+\sqrt{6-x}\) is

  1. A \([1, \infty)\)
  2. B \([1,6]\)
  3. C \((-\infty, 6]\)
  4. D \((-\infty, 6)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \([1,6]\)

Step-by-step Solution

Detailed explanation

\(
f(x)=\sqrt{x-1}+\sqrt{6-x}
\)
Here \(\mathrm{f}(\mathrm{x})\) is defined when
\(x-1 \geq 0\) and \(6-x \geq 0 \quad\) i.e.
\(x \geq 1\) and \(x-6 \leq 0 \quad\) i.e. \(x \geq 1\) and \(x \leq 6\)
\(\therefore\) Domain of \(\mathrm{f}(\mathrm{x})\) is \([1,6]\)