MHT CET · Maths · Three Dimensional Geometry
The distance of the point \((2,-1,0)\) from the plane \(2 x+\mathrm{y}+2 \mathrm{z}+8=0\) is
- A \(\frac{17}{3}\) units
- B \(\frac{13}{3}\) units
- C \(\frac{7}{3}\) units
- D \(\frac{11}{3}\) units
Answer & Solution
Correct Answer
(D) \(\frac{11}{3}\) units
Step-by-step Solution
Detailed explanation
\(\mathrm{d}=\left|\frac{2(2)+(-1)(1)+0+8}{\sqrt{4+1+4}}\right|=\frac{11}{3}\) units
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