MHT CET · Maths · Straight Lines
The distance of the point \((1,2)\) from the line \(x+y=0\) measured parallel to the line \(3 x-y=2\) is
- A \(\frac{3 \sqrt{2}}{8}\) units
- B \(\frac{3 \sqrt{10}}{4}\) units
- C 10 units
- D \(5 \sqrt{5}\) units
Answer & Solution
Correct Answer
(B) \(\frac{3 \sqrt{10}}{4}\) units
Step-by-step Solution
Detailed explanation
Equation of line through \((1,2)\) parallel to \(3x-y=2\): \(y-2=3(x-1) \Rightarrow 3x-y-1=0\). Intersection with \(x+y=0\): \(3x-(-x)=1 \Rightarrow 4x=1 \Rightarrow x=1/4\). Point is \((1/4, -1/4)\).
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