MHT CET · Maths · Three Dimensional Geometry
The distance between the lines \(\frac{x}{2}=\frac{y}{-1}=\frac{z}{2}\) and \(\frac{x-1}{2}=\frac{y-1}{-1}=\frac{z-2}{2}\) is
- A \(\sqrt{3}\) units
- B \(\sqrt{2}\) units
- C 1 unit
- D 2 units
Answer & Solution
Correct Answer
(B) \(\sqrt{2}\) units
Step-by-step Solution
Detailed explanation
Distance between the liens \(=\frac{\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 1-0 & 1-0 & 1-0 \\ 2 & -1 & 2\end{array}\right|}{\sqrt{2^2+(-1)^2+2^2}}\)
\(=\frac{|3 \hat{i}-3 \hat{k}|}{\sqrt{9}}=\frac{\sqrt{3^2+3^2}}{\sqrt{3}}=\sqrt{2}\)
\(=\frac{|3 \hat{i}-3 \hat{k}|}{\sqrt{9}}=\frac{\sqrt{3^2+3^2}}{\sqrt{3}}=\sqrt{2}\)
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