MHT CET · Maths · Pair of Lines
The distance between the lines represented by the equation \(4 x^2+4 x y+y^2-6 x-3 y-4=0\) is
- A \(\frac{1}{\sqrt{5}}\) units
- B \(\frac{1}{5}\) units
- C \(\sqrt{5}\) units
- D 5 units
Answer & Solution
Correct Answer
(C) \(\sqrt{5}\) units
Step-by-step Solution
Detailed explanation
\((2x+y)^2 - 3(2x+y) - 4 = 0\) Let \(Y = 2x+y\). \(Y^2 - 3Y - 4 = 0 \Rightarrow (Y-4)(Y+1) = 0\)
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