MHT CET · Maths · Three Dimensional Geometry
The distance between the line
\(\bar{r}=3 \hat{i}-2 \hat{j}+\hat{k}+\lambda(\hat{i}-2\hat{j})\) and the plane \(\bar{r} \cdot(2 \hat{i}+\hat{j}+\hat{k})=4\) is
- A \(\frac{1}{\sqrt{6}}\) units
- B \(\frac{3}{\sqrt{6}}\) units
- C \(\frac{2}{\sqrt{6}}\) units
- D \(\frac{5}{\sqrt{6}}\) units
Answer & Solution
Correct Answer
(A) \(\frac{1}{\sqrt{6}}\) units
Step-by-step Solution
Detailed explanation
Line direction vector: \(\vec{b} = \hat{i}-2\hat{j}\) Plane normal vector: \(\vec{n} = 2\hat{i}+\hat{j}+\hat{k}\)
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