MHT CET · Maths · Three Dimensional Geometry
The direction cosines of a normal to the plane passing throgh \((4,2,3)\), \((-1,4,2)\) and \((3,2,1)\) are .....
- A \(\frac{-2}{\sqrt{101}}, \frac{3}{\sqrt{101}}, \frac{8}{\sqrt{101}}\)
- B \(\frac{-3}{\sqrt{49}}, \frac{2}{\sqrt{49}}, \frac{6}{\sqrt{49}}\)
- C \(\frac{-4}{\sqrt{101}}, \frac{-9}{\sqrt{101}}, \frac{2}{\sqrt{101}}\)
- D \(\frac{4}{22}, \frac{-12}{22}, \frac{18}{22}\)
Answer & Solution
Correct Answer
(C) \(\frac{-4}{\sqrt{101}}, \frac{-9}{\sqrt{101}}, \frac{2}{\sqrt{101}}\)
Step-by-step Solution
Detailed explanation
\(\vec{AB} = (-1-4, 4-2, 2-3) = (-5, 2, -1)\) \(\vec{AC} = (3-4, 2-2, 1-3) = (-1, 0, -2)\)
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