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MHT CET · Maths · Differential Equations

The differential equation whose solution is \(\mathrm{A} x^2+\mathrm{By}^2=1\) where \(A\) and \(B\) are arbitrary constants is of

  1. A degree 1 and order 2
  2. B degree 2 and order 1
  3. C degree 3 and order 2
  4. D degree 1 and order 3
Verified Solution

Answer & Solution

Correct Answer

(A) degree 1 and order 2

Step-by-step Solution

Detailed explanation

\(Ax^2 + By^2 = 1\) \(2Ax + 2Byy' = 0 \implies Ax + Byy' = 0\)