MHT CET · Maths · Differential Equations
The differential equation whose solution is \(\mathrm{A} x^2+\mathrm{By}^2=1\) where \(A\) and \(B\) are arbitrary constants is of
- A degree 1 and order 2
- B degree 2 and order 1
- C degree 3 and order 2
- D degree 1 and order 3
Answer & Solution
Correct Answer
(A) degree 1 and order 2
Step-by-step Solution
Detailed explanation
\(Ax^2 + By^2 = 1\) \(2Ax + 2Byy' = 0 \implies Ax + Byy' = 0\)
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