MHT CET · Maths · Differential Equations
The differential equation of \(y=\mathrm{e}^x(\mathrm{a} \cos x+\mathrm{b} \sin x)\) is
- A \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-2 \frac{\mathrm{d} y}{\mathrm{~d} x}-y=0\)
- B \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}+2 \frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=0\)
- C \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-2 \frac{\mathrm{d} y}{\mathrm{~d} x}+y=0\)
- D \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-2 \frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=0\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-2 \frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=0\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & y=\mathrm{e}^x(\mathrm{a} \cos x+\mathrm{b} \sin x) \\ & \Rightarrow \frac{\mathrm{d} y}{\mathrm{~d} x}=\mathrm{e}^x(\mathrm{a} \cos x+\mathrm{b} \sin x) \\ & +\mathrm{e}^x(\mathrm{~b} \cos x-\mathrm{a} \sin x) \\ & \Rightarrow \frac{\mathrm{d} y}{\mathrm{~d} x}=y+\mathrm{e}^x(\mathrm{~b} \cos x-\mathrm{a} \sin x) \\ & \Rightarrow \frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}=\frac{\mathrm{d} y}{\mathrm{~d} x}+\mathrm{e}^x(\mathrm{~b} \cos x-\mathrm{a} \sin x) \\ & +\mathrm{e}^x(-\mathrm{b} \sin x-\mathrm{a} \cos x) \\ & \Rightarrow \frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}=\frac{\mathrm{d} y}{\mathrm{~d} x}+\left(\frac{\mathrm{d} y}{\mathrm{~d} x}-y\right)-y \\ & \Rightarrow \frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-2 \frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=0 \\ & \end{aligned}\)
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