MHT CET · Maths · Differential Equations
The differential equation of the family of lines having \(x\) - intercept ' \(\mathrm{a}\) ' and
\(y\) - intercept ' \(\mathrm{b}\) ' is
- A \(\frac{d^{2} y}{d x^{2}}=-1\)
- B \(\frac{d^{2} y}{d x^{2}}=10\)
- C \(\frac{d^{2} y}{d x^{2}}=1\)
- D \(\frac{d^{2} y}{d x^{2}}=0\)
Answer & Solution
Correct Answer
(D) \(\frac{d^{2} y}{d x^{2}}=0\)
Step-by-step Solution
Detailed explanation
Equation of line having \(x-\) intercept \(a\) and \(y\) intercept \(b\) is \(\frac{x}{a}+\frac{y}{b}=1\) i.e. \(b x+a y=a b\) Differentiating w.r.t. x, we get
\(\mathrm{b}+\mathrm{a} \frac{\mathrm{dy}}{\mathrm{dx}}=0 \Rightarrow \mathrm{a} \frac{\mathrm{dy}}{\mathrm{dx}}=-\mathrm{b} \Rightarrow \frac{\mathrm{dy}}{\mathrm{dx}}=\frac{-\mathrm{b}}{\mathrm{a}}\)
Again differentiating w.r.t. \(\mathrm{x}\), we get
\(\frac{d^{2} y}{d x^{2}}=0\)
\(\mathrm{b}+\mathrm{a} \frac{\mathrm{dy}}{\mathrm{dx}}=0 \Rightarrow \mathrm{a} \frac{\mathrm{dy}}{\mathrm{dx}}=-\mathrm{b} \Rightarrow \frac{\mathrm{dy}}{\mathrm{dx}}=\frac{-\mathrm{b}}{\mathrm{a}}\)
Again differentiating w.r.t. \(\mathrm{x}\), we get
\(\frac{d^{2} y}{d x^{2}}=0\)
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