MHT CET · Maths · Differential Equations
The differential equation of family of circles whose centre lies on \(x\) -axis, is
- A \(\frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}+1=0\)
- B \(y \frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}-1=0\)
- C \(y \frac{d^{2} y}{d x^{2}}-\left(\frac{d y}{d x}\right)^{2}-1=0\)
- D \(y \frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}+1=0\)
Answer & Solution
Correct Answer
(D) \(y \frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}+1=0\)
Step-by-step Solution
Detailed explanation
The equation of family of circle having centre at \(x\) -axis is \(x^{2}+y^{2}-2 a x=0\).
On differentiating, we get
\(
2 x+2 y \frac{d y}{d x}-2 a=0
\)
Again, differentiating, we get
\(2+2\left[y \frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}\right]=0\)
\(\Rightarrow y \frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}+1=0\)
On differentiating, we get
\(
2 x+2 y \frac{d y}{d x}-2 a=0
\)
Again, differentiating, we get
\(2+2\left[y \frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}\right]=0\)
\(\Rightarrow y \frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}+1=0\)
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