MHT CET · Maths · Differential Equations
The differential equation of all circles which pass through the origin and whose centre lie on \(\mathrm{Y}\)-axis is
- A \(\left(x^2-y^2\right) \frac{d y}{d x}-2 x y=0\)
- B \(\left(x^2+y^2\right) \frac{d y}{d x}-2 x y=0\)
- C \(\left(x^2+y^2\right) \frac{d y}{d x}+2 x y=0\)
- D \(\left(x^2+y^2\right) \frac{d y}{d x}+2 x y=0\)
Answer & Solution
Correct Answer
(A) \(\left(x^2-y^2\right) \frac{d y}{d x}-2 x y=0\)
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