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MHT CET · Maths · Differential Equations

The degree of the differential equation whose solution is \(y^2=8 a(x+a)\), is

  1. A 2
  2. B 1
  3. C 4
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

We have \(y^2=8 a x+8 a^2\)
Differentiating w.r.t. \(\mathrm{x}\), we get
\(
2 y \frac{d y}{d x}=8 a \quad \Rightarrow \quad a=\left(\frac{y}{4}\right) \frac{d y}{d x}
\)
Substituting value of ' \(a\) ' in eq. (1), we get
\(y^2=8\left(\frac{y}{4}\right) \frac{d y}{d x}(x)+8\left[\left(\frac{y}{4}\right)\left(\frac{d y}{d x}\right)\right]^2=\) \(2 x y \frac{d y}{d x}+\left(\frac{y^2}{2}\right)\left(\frac{d y}{d x}\right)^2 \)
\( \therefore 2 y^2=4 x y\left(\frac{d y}{d x}\right)+y^2\left(\frac{d y}{d x}\right)^2\)
Hence order \(=1\), degree \(=2\)