MHT CET · Maths · Mathematical Reasoning
The contrapositive of the inverse of \(\mathrm{p} \rightarrow(\mathrm{p} \rightarrow \mathrm{q})\) is
- A \((\sim \mathrm{p} \wedge \mathrm{q}) \rightarrow \mathrm{p}\)
- B \((\sim \mathrm{p} \vee \mathrm{q}) \rightarrow \mathrm{p}\)
- C \(\mathrm{p} \rightarrow(\sim \mathrm{p} \vee \mathrm{q})\)
- D \((p \vee q) \rightarrow p\)
Answer & Solution
Correct Answer
(B) \((\sim \mathrm{p} \vee \mathrm{q}) \rightarrow \mathrm{p}\)
Step-by-step Solution
Detailed explanation
Inverse of \(p \rightarrow(p \rightarrow q)\) is
\(\sim \mathrm{p} \rightarrow \sim(\mathrm{p} \rightarrow \mathrm{q})\)
Contrapositive of inverse of \(p \rightarrow(p \rightarrow q)\) is
\(\begin{aligned}
& \sim[\sim(p \rightarrow q)] \rightarrow \sim(\sim p) \\
& \equiv(p \rightarrow q) \rightarrow p \\
& \equiv(\sim p \vee q) \rightarrow p
\end{aligned}\)
\(\sim \mathrm{p} \rightarrow \sim(\mathrm{p} \rightarrow \mathrm{q})\)
Contrapositive of inverse of \(p \rightarrow(p \rightarrow q)\) is
\(\begin{aligned}
& \sim[\sim(p \rightarrow q)] \rightarrow \sim(\sim p) \\
& \equiv(p \rightarrow q) \rightarrow p \\
& \equiv(\sim p \vee q) \rightarrow p
\end{aligned}\)
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