MHT CET · Maths · Matrices
The cofactors of the elements of the first column of the matrix \(A=\left[\begin{array}{ccc}2 & 0 & -1 \\ 3 & 1 & 2 \\ -1 & 1 & 2\end{array}\right]\)
are
- A \(0,-7,2\)
- B \(0,-1,1\)
- C \(0,-8,4\)
- D \(-1,3,-2\)
Answer & Solution
Correct Answer
(B) \(0,-1,1\)
Step-by-step Solution
Detailed explanation
(B)
We know,
\(\begin{array}{l}
C_{i j}=(-1)^{i+j} \times M_{i j} \\
C_{11}=(-1)^{111} \times\left|\begin{array}{ll}
1 & 2 \\
1 & 2
\end{array}\right|=(-1)^{2} \times 0=0 \\
C_{21}=(-1)^{2+1} \times\left|\begin{array}{cc}
0 & -1 \\
1 & 2
\end{array}\right|=(-1)^{3} \times(1)=-1 \\
C_{31}=(-1)^{3+1} \times\left|\begin{array}{cc}
0 & -1 \\
1 & 2
\end{array}\right|=(-1)^{4} \times(1)=1
\end{array}\)
We know,
\(\begin{array}{l}
C_{i j}=(-1)^{i+j} \times M_{i j} \\
C_{11}=(-1)^{111} \times\left|\begin{array}{ll}
1 & 2 \\
1 & 2
\end{array}\right|=(-1)^{2} \times 0=0 \\
C_{21}=(-1)^{2+1} \times\left|\begin{array}{cc}
0 & -1 \\
1 & 2
\end{array}\right|=(-1)^{3} \times(1)=-1 \\
C_{31}=(-1)^{3+1} \times\left|\begin{array}{cc}
0 & -1 \\
1 & 2
\end{array}\right|=(-1)^{4} \times(1)=1
\end{array}\)
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