MHT CET · Maths · Ellipse
The co-ordinates of foci of the ellipse \(16 x^{2}+9 y^{2}=144\) are
- A \((\pm 7,0)\)
- B \((0, \pm \sqrt{7})\)
- C \((\pm \sqrt{7}, 0)\)
- D \((0, \pm 7)\)
Answer & Solution
Correct Answer
(D) \((0, \pm 7)\)
Step-by-step Solution
Detailed explanation
\(\frac{16 x^{2}}{144}+\frac{9 y^{2}}{144}=\frac{144}{144} \Rightarrow \frac{x^{2}}{9}+\frac{y^{2}}{16}=1\) \(a^2=16, b^2=9\)
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