MHT CET · Maths · Hyperbola
The centre of the hyperbola \(9 x^{2}-36 x-16 y^{2}+96 y-252=0\) is Ans \(\times\) i. \((-2,-3)\)
- A \((-2,-3)\)
- B \((2,-3)\)
- C \((-2,3)\)
- D \((2,3)\)
Answer & Solution
Correct Answer
(D) \((2,3)\)
Step-by-step Solution
Detailed explanation
\(9 x^{2}-36 x-16 y^{2}+96 y-252=0\)
\(9(x-2)^{2}-16(y-3)^{2}=\frac{22}{532}\)
center \(\rightarrow(2,3)\)
\(9(x-2)^{2}-16(y-3)^{2}=\frac{22}{532}\)
center \(\rightarrow(2,3)\)
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