MHT CET · Maths · Three Dimensional Geometry
The Cartesian equation of the plane \(\bar{r}=(2 \hat{i}-3 \hat{j})+\lambda(\hat{i}+2 \hat{j}-\hat{k})+\mu(2 \hat{i}+3 \hat{j}+\hat{k})\) is
- A \(5 x-4 y+z=22\)
- B \(5 x-3 y+z=19\)
- C \(5 x-3 y-z=19\)
- D \(5 x-4 y-z=22\)
Answer & Solution
Correct Answer
(C) \(5 x-3 y-z=19\)
Step-by-step Solution
Detailed explanation
\(\bar{n} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 1 & 2 & -1 \\ 2 & 3 & 1 \end{vmatrix} = (2-(-3))\hat{i} - (1-(-2))\hat{j} + (3-4)\hat{k} = 5\hat{i} - 3\hat{j} - \hat{k}\) \(d = (2\hat{i}-3\hat{j}) \cdot (5\hat{i}-3\hat{j}-\hat{k}) = 2(5) + (-3)(-3) + 0(-1) = 10 + 9 = 19\)
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