MHT CET · Maths · Three Dimensional Geometry
The Cartesian equation of the line which passes through the points \((3,1,2)\) and \((-1,2,1)\) is
- A \(\frac{x-3}{-4}=\frac{y-1}{1}=\frac{z-2}{1}\)
- B \(\frac{x-3}{-4}=\frac{y-1}{1}=\frac{z-2}{-1}\)
- C \(\frac{x-3}{-4}=\frac{y-1}{-1}=\frac{z-2}{-1}\)
- D \(\frac{x-3}{-4}=\frac{y-1}{-1}=\frac{z-2}{1}\)
Answer & Solution
Correct Answer
(B) \(\frac{x-3}{-4}=\frac{y-1}{1}=\frac{z-2}{-1}\)
Step-by-step Solution
Detailed explanation
The required equation of the line is
\(\begin{aligned} & \frac{x-3}{-1-3}=\frac{y-1}{2-1}=\frac{z-2}{1-2} \\ & \Rightarrow \frac{x-3}{-4}=\frac{y-1}{1}=\frac{z-2}{-1}\end{aligned}\)
\(\begin{aligned} & \frac{x-3}{-1-3}=\frac{y-1}{2-1}=\frac{z-2}{1-2} \\ & \Rightarrow \frac{x-3}{-4}=\frac{y-1}{1}=\frac{z-2}{-1}\end{aligned}\)
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