MHT CET · Maths · Probability
The c. d. f. \(F(x)\) associated with p. d. f. \(f(x)=3\left(1-2 x^{2}\right)\) if \(0 < x < 1\)
\(=0\)
otherwise
is \(k\left(x-\frac{2 x^{3}}{k}\right)\), then value of \(k\) is
- A 3
- B 1
- C \(\frac{1}{3}\)
- D \(\frac{1}{6}\)
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
(D)
Since \(f(x)\) is p.d.f. of r.v. therefore c.d.f. is
\(F(x)=\int_{0}^{1} 3\left(1-2 x^{2}\right) d x=\left[3\left(x-\frac{2 x^{3}}{3}\right)\right]_{0}^{1}\)
From given data, we get \(k=3\)
Since \(f(x)\) is p.d.f. of r.v. therefore c.d.f. is
\(F(x)=\int_{0}^{1} 3\left(1-2 x^{2}\right) d x=\left[3\left(x-\frac{2 x^{3}}{3}\right)\right]_{0}^{1}\)
From given data, we get \(k=3\)
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