MHT CET · Maths · Differential Equations
The bacteria increases at the rate proportional to the number of bacteria present. If
the original number ' \(\mathrm{N}^{\prime}\) doubles in 4 hours then the number of bacteria in 12 hours
will be
- A \(3 \mathrm{~N}\)
- B \(4 \mathrm{~N}\)
- C \(6 \mathrm{~N}\)
- D \(8 \mathrm{~N}\)
Answer & Solution
Correct Answer
(B) \(4 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
(B)
Number of bacteria at the beginning \(=N\). The number doubles in every \(4 \mathrm{hrs}\).
\(\therefore\) Number of bacteria after \(4 \mathrm{hrs}=2 \mathrm{~N}\), after \(8 \mathrm{hrs}=4 \mathrm{~N}\), after \(12 \mathrm{hrs}=8 \mathrm{~N}\)
Number of bacteria at the beginning \(=N\). The number doubles in every \(4 \mathrm{hrs}\).
\(\therefore\) Number of bacteria after \(4 \mathrm{hrs}=2 \mathrm{~N}\), after \(8 \mathrm{hrs}=4 \mathrm{~N}\), after \(12 \mathrm{hrs}=8 \mathrm{~N}\)
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