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MHT CET · Maths · Complex Number

The argument of \(\frac{1+i \sqrt{3}}{\sqrt{3}+i}, i=\sqrt{-1}\) is

  1. A \(\frac{\pi}{3}\)
  2. B \(\frac{\pi}{4}\)
  3. C \(\frac{\pi}{6}\)
  4. D \(\frac{\pi}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\pi}{6}\)

Step-by-step Solution

Detailed explanation

\(\text {Let } z=\frac{1+i \sqrt{3}}{\sqrt{3}+i} \)
\( = \frac{(1+i \sqrt{3})(\sqrt{3}-i)}{(\sqrt{3}+i)(\sqrt{3}-i)} \)
\( \therefore z =\frac{\sqrt{3}}{2}+\frac{1}{2} i\)
Argument of
\(z =\tan ^{-1}\left(\frac{b}{a}\right) \)
\(=\tan ^{-1}\left(\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\right) \)
\(=\tan ^{-1}\left(\frac{1}{\sqrt{3}}\right) \)
\(=\frac{\pi}{6}\)