MHT CET · Maths · Area Under Curves
The area of smaller part between the circle \(x^2+y^2=4\) and the line \(x=1\) is _______ sq.units.
- A \(\frac{4 \pi}{3}-\sqrt{3}\)
- B \(\frac{8 \pi}{3}-\sqrt{3}\)
- C \(\frac{4 \pi}{3}+\sqrt{3}\)
- D \(\frac{5 \pi}{3}+\sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{4 \pi}{3}-\sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(A = r^2 \cos^{-1}\left(\frac{x}{r}\right) - x\sqrt{r^2-x^2}\) \(A = 2^2 \cos^{-1}\left(\frac{1}{2}\right) - 1\sqrt{2^2-1^2}\)
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