MHT CET · Maths · Vector Algebra
The area of a parallelogram whose diagonals are the vectors \(2 \bar{a}-\bar{b}\) and \(4 \bar{a}-5 \bar{b}\), where \(\bar{a}\) and \(\overline{\mathrm{b}}\) are unit vectors forming an angle of \(45^{\circ}\) is
- A \(3 \sqrt{2}\) sq. units
- B \(\frac{3}{\sqrt{2}}\) sq. units
- C \(\sqrt{2}\) sq. units
- D \(\frac{\sqrt{2}}{3}\) sq. units
Answer & Solution
Correct Answer
(B) \(\frac{3}{\sqrt{2}}\) sq. units
Step-by-step Solution
Detailed explanation
The area of a parallelogram with diagonals \( \vec{d_1} \) and \( \vec{d_2} \) is \( A = \frac{1}{2} | \vec{d_1} \times \vec{d_2} | \). \( \vec{d_1} = 2\bar{a} - \bar{b} \), \( \vec{d_2} = 4\bar{a} - 5\bar{b} \)
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