MHT CET · Maths · Area Under Curves
The area inside the parabola \(y^2=4 a x\), between the lines \(x=a\) and \(x=4 a\) is equal to
- A \(4 a^2\) sq. units
- B \(8 a^2\) sq. units
- C \(\frac{56 a^2}{3}\) sq. units
- D \(\frac{35 a^2}{3}\) sq. units
Answer & Solution
Correct Answer
(C) \(\frac{56 a^2}{3}\) sq. units
Step-by-step Solution
Detailed explanation
\(A = \int_{a}^{4a} 2\sqrt{4ax} \, dx\) \(A = 4\sqrt{a} \int_{a}^{4a} x^{1/2} \, dx\)
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