MHT CET · Maths · Area Under Curves
The area included between the parabolas \(y^{2}=5 x\) and \(x^{2}=5 y\) is
- A \(\frac{25}{7}\) sq. units
- B \(\frac{25}{3}\) sq. units
- C \(\frac{25}{4}\) sq. units
- D \(25 \mathrm{sq}\). units
Answer & Solution
Correct Answer
(B) \(\frac{25}{3}\) sq. units
Step-by-step Solution
Detailed explanation
(C)
Prabolas\(y^{2}=5 x\) and \(x^{2}=5 y\) intersect at
\(\frac{x^{2}}{5}=5 x \Rightarrow x^{*}=5^{3} x \Rightarrow x\left(x^{3}-125\right)=0 \Rightarrow x=\) \(0.5 \Rightarrow y=0,5\)
Let points of intersection be \(Q(0,0)\) and \(A(5.5)\). Required area is shaded. Ares included becween the parabolas
\(=\int \sqrt{5 x}-\frac{x}{5} d x\)
\(\left.=\frac{\sqrt{5} x}{3}-\frac{x^{3}}{15}=\frac{2}{3}\right)(\sqrt{5})(5 \sqrt{5})-\frac{125}{15}\)
\(=\frac{50}{3}-\frac{125}{15}=\frac{25}{3}\)

Prabolas\(y^{2}=5 x\) and \(x^{2}=5 y\) intersect at
\(\frac{x^{2}}{5}=5 x \Rightarrow x^{*}=5^{3} x \Rightarrow x\left(x^{3}-125\right)=0 \Rightarrow x=\) \(0.5 \Rightarrow y=0,5\)
Let points of intersection be \(Q(0,0)\) and \(A(5.5)\). Required area is shaded. Ares included becween the parabolas
\(=\int \sqrt{5 x}-\frac{x}{5} d x\)
\(\left.=\frac{\sqrt{5} x}{3}-\frac{x^{3}}{15}=\frac{2}{3}\right)(\sqrt{5})(5 \sqrt{5})-\frac{125}{15}\)
\(=\frac{50}{3}-\frac{125}{15}=\frac{25}{3}\)

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