MHT CET · Maths · Area Under Curves
The area (in sq. units) of the region bounded by curves \(y=3 x+1, y=4 x+1\) and \(x=3\) is
- A \(\frac{7}{2}\)
- B \(\frac{9}{5}\)
- C \(\frac{9}{2}\)
- D \(\frac{7}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{9}{2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \text { Required area } & =\cdot \int_0^3[4 x+1-(3 x+1)] \mathrm{d} x \\ & =\int_0^3 x \mathrm{~d} x \\ & =\left[\frac{x^2}{2}\right]_0^3 \\ & =\frac{9}{2} \text { sq. units }\end{aligned}\)
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