MHT CET · Maths · Area Under Curves
The area (in sq. units) bounded by the curves \(y=\sqrt{x}, 2 y-x+3=0\), \(\mathrm{X}\)-axis and lying in the first quadrant, is
- A 6
- B \(\frac{27}{4}\)
- C 9
- D 18
Answer & Solution
Correct Answer
(C) 9
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \int_0^9 \sqrt{x} \mathrm{~d} x-\frac{1}{2} \times 6 \times 3 \\ & =\frac{2}{3}\left[x^{3 / 2}\right]_0^9-9\end{aligned}\)
\(=\frac{2}{3} \times 27-9=9\)
\(=\frac{2}{3} \times 27-9=9\)
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