MHT CET · Maths · Area Under Curves
The area bounded by the curve \(\mathrm{y}=4 x-x^2\) and X - axis in square units, is \(\qquad\)
- A \(\frac{32}{3}\)
- B 16
- C 32
- D \(21 \frac{1}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{32}{3}\)
Step-by-step Solution
Detailed explanation
Intersection with X-axis: \(4x - x^2 = 0 \Rightarrow x(4 - x) = 0 \Rightarrow x = 0, x = 4\). Area \(A = \int_{0}^{4} (4x - x^2) \, dx\).
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