MHT CET · Maths · Three Dimensional Geometry
The angle between the lines \(x-3 \mathrm{y}-4=0,4 \mathrm{y}-\mathrm{z}+5=0\) and \(x+3 \mathrm{y}-11=0,2 \mathrm{y}-\mathrm{z}+6=0\) is
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{6}\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
Direction vector for line 1: \(\vec{d_1} = \langle 1,-3,0 \rangle \times \langle 0,4,-1 \rangle = \langle 3,1,4 \rangle\). Direction vector for line 2: \(\vec{d_2} = \langle 1,3,0 \rangle \times \langle 0,2,-1 \rangle = \langle -3,1,2 \rangle\).
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