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MHT CET · Maths · Three Dimensional Geometry

The angle between the lines \(\frac{x-1}{l}=\frac{y+1}{m}=\frac{z}{n}\) and \(\frac{x+1}{m}=\frac{y-3}{n}=\frac{z-1}{l}\), where \(l>\mathrm{m}>\mathrm{n}\) and \(\mathrm{l}, \mathrm{m}, \mathrm{n}\) are roots of the equation \(x^3+x^2-4 x-4=0\), is

  1. A \(\cos ^{-1}\left(\frac{2}{9}\right)\)
  2. B \(\cos ^{-1}\left(\frac{-4}{9}\right)\)
  3. C \(\cos ^{-1}\left(\frac{2}{3}\right)\)
  4. D \(\cos ^{-1}\left(\frac{1}{9}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\cos ^{-1}\left(\frac{-4}{9}\right)\)

Step-by-step Solution

Detailed explanation

\(x^3+x^2-4 x-4=0 \Rightarrow x^2(x+1)-4(x+1)=0 \Rightarrow (x^2-4)(x+1)=0\) \((x-2)(x+2)(x+1)=0 \Rightarrow x=2, -2, -1\)