ExamBro
ExamBro
MHT CET · Maths · Three Dimensional Geometry

The angle between the lines \(\frac{x-1}{4}=\frac{y-3}{1}=\frac{z}{8}\) and \(\frac{x-2}{2}=\frac{y+1}{2}=\frac{z-4}{1}\) is

  1. A \(\sin ^{-1}\left(\frac{2}{3}\right)\)
  2. B \(\cos ^{-1}\left(\frac{2}{3}\right)\)
  3. C \(\cos ^{-1}\left(\frac{1}{3}\right)\)
  4. D \(\sin ^{-1}\left(\frac{1}{3}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\cos ^{-1}\left(\frac{2}{3}\right)\)

Step-by-step Solution

Detailed explanation

\(\cos \theta=\left|\frac{4(2)+1(2)+8(1)}{\sqrt{4^{2}+1^{2}+8^{2}} \sqrt{2^{2}+2^{2}+1^{2}}}\right|=\left|\frac{8+1+8}{\sqrt{81} \cdot \sqrt{9}}\right|=\frac{18}{27}\)
\(\therefore \cos \theta=\frac{2}{3} \Rightarrow \theta=\cos ^{-1}\left(\frac{2}{3}\right)\)