MHT CET · Maths · Three Dimensional Geometry
The angle between the lines \(\bar{r}=(3 \hat{i}+2 \hat{j}-4 \hat{k})+\lambda(\hat{i}+2 \hat{j}+2 \hat{k})\) and \(\bar{r}=(5 \hat{i}-2 \widehat{k})+\mu(3 \hat{i}+2 \hat{j}+6 \widehat{k})\)
- A \(\cos ^{-1}\left(\frac{20}{21}\right)\)
- B \(\cos ^{-1}\left(\frac{4}{21}\right)\)
- C \(\cos ^{-1}\left(\frac{16}{21}\right)\)
- D \(\cos ^{-1}\left(\frac{19}{21}\right)\)
Answer & Solution
Correct Answer
(D) \(\cos ^{-1}\left(\frac{19}{21}\right)\)
Step-by-step Solution
Detailed explanation
\(\text {Required angle }=\cos ^{-1}\) \(\left(\frac{(\hat{i}+2 \hat{j}+2 \widehat{k}) \cdot(3 \hat{i}+2 \hat{j}+6 \hat{k})}{\sqrt{1^2+2^2+2^2} \times \sqrt{3^2+2^2+6^2}}\right) \)
\( {\left[\because \theta=\cos ^{-1}\left(\frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}\right)\right]} \)
\( =\cos ^{-1}\left(\frac{1 \times 3+2 \times 2+2 \times 6}{3 \times 7}\right) \)
\( =\cos ^{-1}\left(\frac{19}{21}\right)\)
\( {\left[\because \theta=\cos ^{-1}\left(\frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}\right)\right]} \)
\( =\cos ^{-1}\left(\frac{1 \times 3+2 \times 2+2 \times 6}{3 \times 7}\right) \)
\( =\cos ^{-1}\left(\frac{19}{21}\right)\)
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