MHT CET · Maths · Three Dimensional Geometry
The angle between the lines \(3 x=2 y=-z\) and \(-x=6 y=-4 z\) is
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{2}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
\(\vec{d_1} = \langle 1/3, 1/2, -1 \rangle \equiv \langle 2, 3, -6 \rangle\) \(\vec{d_2} = \langle -1, 1/6, -1/4 \rangle \equiv \langle -12, 2, -3 \rangle\)
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