MHT CET · Maths · Application of Derivatives
The angle between the curves \(x \mathrm{y}=6\) and \(x^2 \mathrm{y}=12\) is
- A \(\tan ^{-1} \frac{3}{11}\)
- B \(\tan ^{-1} \frac{11}{3}\)
- C \(\tan ^{-1} \frac{2}{11}\)
- D \(\tan ^{-1} \frac{1}{11}\)
Answer & Solution
Correct Answer
(A) \(\tan ^{-1} \frac{3}{11}\)
Step-by-step Solution
Detailed explanation
The intersection point of \(xy=6\) and \(x^2y=12\) is \((2,3)\). For \(xy=6\), \(\frac{dy}{dx} = -\frac{y}{x}\). At \((2,3)\), \(m_1 = -\frac{3}{2}\).
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