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MHT CET · Maths · Application of Derivatives

The angle \(\theta\), at which the curves \(\mathrm{y}=3^x\) and \(\mathrm{y}=7^x\) intersect, is given by

  1. A \(\tan \theta=\frac{\log \left(\frac{3}{7}\right)}{1+(\log 3)(\log 7)}\)
  2. B \(\tan \theta=\frac{\log \left(7\right)}{1+(\log 3)(\log 7)}\)
  3. C \(\tan \theta=\frac{\log \left(\frac{3}{7}\right)}{1-(\log 3)(\log 7)}\)
  4. D \(\tan \theta=\frac{\log \left(\frac{7}{3}\right)}{1-(\log 3)(\log 7)}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\tan \theta=\frac{\log \left(\frac{3}{7}\right)}{1+(\log 3)(\log 7)}\)

Step-by-step Solution

Detailed explanation

\(3^x = 7^x \Rightarrow x = 0\) \(m_1 = \frac{d}{dx}(3^x) |_{x=0} = 3^0 \ln 3 = \ln 3\)