MHT CET · Maths · Straight Lines
The acute angle included between the lines \(x \sin \theta-y \cos \theta=5\) and
\(x \sin \propto-y \cos \propto+11=0\) is
- A \(|\theta-\propto|\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\theta+\propto\)
Answer & Solution
Correct Answer
(A) \(|\theta-\propto|\)
Step-by-step Solution
Detailed explanation
Slope of line \(x \sin \theta-y \cos \theta=5\) is \(m_{1}=\frac{\sin \theta}{\cos \theta}=\tan \theta\) Slope of line \(x \sin \alpha-y \sin \alpha+11=0\) is \(m_{2}=\frac{\sin \alpha}{\cos \alpha}=\tan \alpha\) Let \(\beta\) be the angle between the lines
\(\begin{aligned}
\tan \beta &=\left|\frac{\tan \theta-\tan \alpha}{1+\tan \alpha \tan \alpha}\right| \Rightarrow \tan \beta=\tan (\theta-\alpha) \\
\beta &=|\theta-\alpha|
\end{aligned}\)
\(\begin{aligned}
\tan \beta &=\left|\frac{\tan \theta-\tan \alpha}{1+\tan \alpha \tan \alpha}\right| \Rightarrow \tan \beta=\tan (\theta-\alpha) \\
\beta &=|\theta-\alpha|
\end{aligned}\)
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