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MHT CET · Maths · Application of Derivatives

The abscissae of the points of the curve \(\mathrm{y}=x^3\) are in the interval \([-2,2]\), where the slope of the tangents can be obtained by 5. Mean Value Theorem for the interval \([-2,2]\) are

  1. A \(0\)
  2. B \(\pm \sqrt{3}\)
  3. C \(\pm \frac{2}{\sqrt{3}}\)
  4. D \(\frac{\sqrt{3}}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\pm \frac{2}{\sqrt{3}}\)

Step-by-step Solution

Detailed explanation

\(f(x) = x^3\) \(f(-2) = (-2)^3 = -8\)