MHT CET · Maths · Application of Derivatives
The abscissae of the points of the curve \(\mathrm{y}=x^3\) are in the interval \([-2,2]\), where the slope of the tangents can be obtained by 5. Mean Value Theorem for the interval \([-2,2]\) are
- A \(0\)
- B \(\pm \sqrt{3}\)
- C \(\pm \frac{2}{\sqrt{3}}\)
- D \(\frac{\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(C) \(\pm \frac{2}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
\(f(x) = x^3\) \(f(-2) = (-2)^3 = -8\)
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