MHT CET · Maths · Differential Equations
Solution of the differential equation \(\frac{d y}{d x}+2 y=e^{-x}\) is
- A \(y e^{x}=x+c\)
- B \(y e^{2 x}=x+c\)
- C \(y e^{x}=e^{2 x}+c\)
- D \(y e^{2 x}=e^{x}+c\)
Answer & Solution
Correct Answer
(D) \(y e^{2 x}=e^{x}+c\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{dy}}{\mathrm{dx}}+2 \mathrm{y}=\mathrm{e}^{-x}\)
I.F. \(=\mathrm{e}^{2 \int \mathrm{dx}}=\mathrm{e}^{2 \mathrm{x}}\)
\(\therefore \mathrm{ye}^{2 \mathrm{x}}=\int \mathrm{e}^{2 \mathrm{x}} \cdot \mathrm{e}^{-\mathrm{x}} \mathrm{dx}+\mathrm{c}\)
\(\therefore \mathrm{y} \mathrm{e}^{2 \mathrm{x}}=\int \mathrm{e}^{\mathrm{x}} \mathrm{dx}+\mathrm{c} \Rightarrow \mathrm{ye}^{2 \mathrm{x}}=\mathrm{e}^{\mathrm{x}}+\mathrm{c}\)
I.F. \(=\mathrm{e}^{2 \int \mathrm{dx}}=\mathrm{e}^{2 \mathrm{x}}\)
\(\therefore \mathrm{ye}^{2 \mathrm{x}}=\int \mathrm{e}^{2 \mathrm{x}} \cdot \mathrm{e}^{-\mathrm{x}} \mathrm{dx}+\mathrm{c}\)
\(\therefore \mathrm{y} \mathrm{e}^{2 \mathrm{x}}=\int \mathrm{e}^{\mathrm{x}} \mathrm{dx}+\mathrm{c} \Rightarrow \mathrm{ye}^{2 \mathrm{x}}=\mathrm{e}^{\mathrm{x}}+\mathrm{c}\)
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