MHT CET · Maths · Differential Equations
Solution of \((2 y-x) \frac{d y}{d x}=1\) is
- A \(x=2(y-1)+c \mathrm{e}^{-\mathrm{y}}\), where c is the constant of integration
- B \(x=2(y-1)+\mathrm{ce}^{-x}\), where c is the constant of integration
- C \(\mathrm{y}=2(x-1)+\mathrm{ce}^{-x}\), where c is the constant of integration
- D \(\mathrm{y}=2(x-1)+\mathrm{ce}^{-\mathrm{y}}\), where c is the constant of integration
Answer & Solution
Correct Answer
(A) \(x=2(y-1)+c \mathrm{e}^{-\mathrm{y}}\), where c is the constant of integration
Step-by-step Solution
Detailed explanation
\(\frac{d x}{d y} + x = 2y\) IF \( = e^{\int 1 dy} = e^y\)
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