MHT CET · Maths · Mathematical Reasoning
\(\mathrm{S}_1:\) If -7 is an integer, the \(\sqrt{-7}\) is a complex number
\(\mathrm{S}_2:-7\) is not an integer or \(\sqrt{-7}\) is a complex number
- A \(\mathrm{S}_1\) and \(\mathrm{S}_2\) are converse statements of each other
- B \(S_1\) and \(S_2\) are negations of each other
- C \(\mathrm{S}_1\) and \(\mathrm{S}_2\) are equivalent statements
- D \(S_1\) and \(S_2\) are contrapositive of each other
Answer & Solution
Correct Answer
(C) \(\mathrm{S}_1\) and \(\mathrm{S}_2\) are equivalent statements
Step-by-step Solution
Detailed explanation
Let \(p:-7\) is an integer.
\(\mathrm{q}: \sqrt{-7}\) is a complex number.
Logical form of \(\mathrm{S}_1 \equiv \mathrm{p} \rightarrow \mathrm{q}\)
Logical form of \(\mathrm{S}_2 \equiv \sim \mathrm{p} \vee \mathrm{q}\)
We know that \(\mathrm{p} \rightarrow \mathrm{q} \equiv \sim \mathrm{p} \vee \mathrm{q}\)
\(\therefore \mathrm{S}_1\) and \(\mathrm{S}_2\) are equivalent statements.
\(\mathrm{q}: \sqrt{-7}\) is a complex number.
Logical form of \(\mathrm{S}_1 \equiv \mathrm{p} \rightarrow \mathrm{q}\)
Logical form of \(\mathrm{S}_2 \equiv \sim \mathrm{p} \vee \mathrm{q}\)
We know that \(\mathrm{p} \rightarrow \mathrm{q} \equiv \sim \mathrm{p} \vee \mathrm{q}\)
\(\therefore \mathrm{S}_1\) and \(\mathrm{S}_2\) are equivalent statements.
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