MHT CET · Maths · Permutation Combination
Number of different nine digit numbers, that can be formed from the digits in the number 223355888 by rearranging its digits, so that the odd digits occupy even positions, is
- A 16
- B 40
- C 60
- D 180
Answer & Solution
Correct Answer
(C) 60
Step-by-step Solution
Detailed explanation
Since \(3,3,5\), 5, i.e., odd digits occupy even positions and \(2,2,8,8,8\) occupy remaining 5 odd places.
\(\therefore\) Required number of ways \(=\frac{4!}{2!2!} \cdot \frac{5!}{2!3!}\)
\(=6 \times 10=60\)
\(\therefore\) Required number of ways \(=\frac{4!}{2!2!} \cdot \frac{5!}{2!3!}\)
\(=6 \times 10=60\)
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