MHT CET · Maths · Linear Programming
Maximum value of \(Z=5 x+2 y\), subject to \(2 x-y \geq 2, x+2 y \leq 8\) and \(x, y \geq 0\) is
- A \(28\)
- B \(25.6\)
- C \(40\)
- D \(17.6\)
Answer & Solution
Correct Answer
(C) \(40\)
Step-by-step Solution
Detailed explanation

\(\mathrm{z}=5 x+2 y\)
\(\mathrm{z}_{\text {max. }}=5 \times 8+2 \times 0=40\)
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