MHT CET · Maths · Linear Programming
Maximum value of \(\mathrm{z}=3 x+4 \mathrm{y}\) subject to \(x-\mathrm{y} \leqslant-1, \quad-x+\mathrm{y} \leqslant 0, \quad x, \mathrm{y} \geqslant 0\) is given by
- A 1
- B 4
- C 6
- D does not exist
Answer & Solution
Correct Answer
(D) does not exist
Step-by-step Solution
Detailed explanation
The constraints are: \(y \ge x+1\)
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