MHT CET · Maths · Matrices
Matrix \(A\) is non-singular matrix and \((A-3 I)(A-5 I)=0\), then \(\frac{15}{8} A^{-1}=\) _________
- A \(\mathrm{I}-8 \mathrm{~A}\)
- B \(2 \mathrm{I}-\frac{1}{15} \mathrm{~A}\)
- C \(\mathrm{I}-\frac{1}{8} \mathrm{~A}\)
- D \(8 \mathrm{I}-15 \mathrm{~A}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{I}-\frac{1}{8} \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
\((A-3 I)(A-5 I)=0\) \(A^2 - 8A + 15I = 0\)
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