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MHT CET · Maths · Straight Lines

Locus of the point of intersection of perpendicular tangents to the circle \(x^{2}+y^{2}=16\) is

  1. A \(x^{2}+y^{2}=8\)
  2. B \(x^{2}+y^{2}=32\)
  3. C \(x^{2}+y^{2}=64\)
  4. D \(x^{2}+y^{2}=16\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x^{2}+y^{2}=32\)

Step-by-step Solution

Detailed explanation

We know that, if two perpendicular tangents to the circle \(x^{2}+y^{2}=a^{2}\) meet at \(P\), then the point
\(P\) lies on a director circle. \(\therefore\) Required locus is \(x^{2}+y^{2}=32\)