MHT CET · Maths · Complex Number
Let \(z\) be a complex number such that \(|z|+z=3+i, i=\sqrt{-1}\), then \(|z|\) is equal to
- A \(\frac{5}{4}\)
- B \(\frac{\sqrt{41}}{4}\)
- C \(\frac{\sqrt{34}}{3}\)
- D \(\frac{5}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & |z|+z=3+i \\ & \Rightarrow \sqrt{x^2+y^2}+x+i y=3+i[\text { let } z=x+i y] \\ & \Rightarrow \sqrt{x^2+y^2}+x=3 \text { and } y=1 \\ & \Rightarrow \sqrt{x^2+1^2}+x=3 \\ & \Rightarrow x^2+1=(3-x)^2 \\ & \Rightarrow x=\frac{4}{3} \\ & \Rightarrow|z|=\sqrt{x^2+y^2}=\sqrt{\left(\frac{4}{3}\right)^2+1^2}=\frac{5}{3}\end{aligned}\)
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