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MHT CET · Maths · Complex Number

Let \(z\) be a complex number such that \(|z|+z=3+i, i=\sqrt{-1}\), then \(|z|\) is equal to

  1. A \(\frac{5}{4}\)
  2. B \(\frac{\sqrt{41}}{4}\)
  3. C \(\frac{\sqrt{34}}{3}\)
  4. D \(\frac{5}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{5}{3}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & |z|+z=3+i \\ & \Rightarrow \sqrt{x^2+y^2}+x+i y=3+i[\text { let } z=x+i y] \\ & \Rightarrow \sqrt{x^2+y^2}+x=3 \text { and } y=1 \\ & \Rightarrow \sqrt{x^2+1^2}+x=3 \\ & \Rightarrow x^2+1=(3-x)^2 \\ & \Rightarrow x=\frac{4}{3} \\ & \Rightarrow|z|=\sqrt{x^2+y^2}=\sqrt{\left(\frac{4}{3}\right)^2+1^2}=\frac{5}{3}\end{aligned}\)