MHT CET · Maths · Three Dimensional Geometry
Let the line \(\frac{x-2}{3}=\frac{y-1}{-5}=\frac{z+2}{2}\) lie in the plane \(x+3 y-\alpha z+\beta=0\), then the value of \((\beta-\alpha)\) is equal to
- A \(1\)
- B \(13\)
- C \(7\)
- D \(-6\)
Answer & Solution
Correct Answer
(B) \(13\)
Step-by-step Solution
Detailed explanation
\( (3)(1)+(-5)(3)+(2)(-\alpha)=0 \) \( 3-15-2\alpha=0 \)
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