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MHT CET · Maths · Indefinite Integration

Let \(I=\int \tan ^{-1}\left(\frac{2 x}{1-x^2}\right) d x\), then \(I-2 x \tan ^{-1} x=\)

  1. A \(\log \left(1+x^2\right)+\mathrm{c}\)
  2. B \(-\log \left(1+x^2\right)+\mathrm{c}\)
  3. C \(-\log \left(1-x^2\right)+c\)
  4. D \(\log \left|\frac{2 \mathrm{x}}{1-\mathrm{x}^2}\right|+\mathrm{c}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-\log \left(1+x^2\right)+\mathrm{c}\)

Step-by-step Solution

Detailed explanation

\( \tan ^{-1}\left(\frac{2 x}{1-x^2}\right) = 2 \tan ^{-1} x \) \( I = \int 2 \tan ^{-1} x \, dx \)