MHT CET · Maths · Definite Integration
Let \(f: \mathbb{R} \rightarrow \mathbb{R}\) is differentiable function having \(f(3)=3, f^{\prime}(3)=\frac{1}{27}\) and \(\mathrm{g}(\mathrm{x})=\left\{\begin{array}{ccc}\int_3^{\mathrm{f}(x)} \frac{3 \mathrm{t}^2}{x-3} \mathrm{dt} & , & \text { if } x \neq 3 \\ \mathrm{~K} & , & \text { if } x=3\end{array}\right.\) is continuous at \(x=3\), then \(\mathrm{K}=\)
- A 1
- B 3
- C \(\frac{1}{3}\)
- D 9
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
\(\mathrm{K} = \lim_{x \to 3} \frac{\int_3^{\mathrm{f}(x)} 3 \mathrm{t}^2 \mathrm{dt}}{x-3}\) \(\mathrm{K} = \lim_{x \to 3} \frac{\frac{\mathrm{d}}{\mathrm{dx}} (\int_3^{\mathrm{f}(x)} 3 \mathrm{t}^2 \mathrm{dt})}{\frac{\mathrm{d}}{\mathrm{dx}} (x-3)}\)
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